What is the inverse of (9x^2-64)/(6x^2-4x-32) ?

The inverse of (9x^2-64)/(6x^2-4x-32) is (8-4x)/(2x-3)

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inverse of (9x^2-64)/(6x^2-4x-32)

inverse

\frac{9 x ^{2} - 64}{6 x ^{2} - 4 x - 32}

\frac{8 - 4 x}{2 x - 3}

Solution steps

y = \frac{9 x ^{2} - 64}{6 x ^{2} - 4 x - 32}

Replace

x

with

y

x = \frac{9 y ^{2} - 64}{6 y ^{2} - 4 y - 32}

Solve for

y, x = \frac{9 y ^{2} - 64}{6 y ^{2} - 4 y - 32}

\frac{8 - 4 x}{2 x - 3}

What is the inverse of (9x^2-64)/(6x^2-4x-32) ?
The inverse of (9x^2-64)/(6x^2-4x-32) is (8-4x)/(2x-3)