What is the inverse of (x^2+1)/(x^2+5) ?

The inverse of (x^2+1)/(x^2+5) is sqrt((1-5x)/(x-1)),-sqrt((1-5x)/(x-1))

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inverse of (x^2+1)/(x^2+5)

inverse

\frac{x ^{2} + 1}{x ^{2} + 5}

\frac{1 - 5 x}{x - 1}, - \frac{1 - 5 x}{x - 1}

Solution steps

y = \frac{x ^{2} + 1}{x ^{2} + 5}

Replace

x

with

y

x = \frac{y ^{2} + 1}{y ^{2} + 5}

Solve for

y, x = \frac{y ^{2} + 1}{y ^{2} + 5}

\frac{1 - 5 x}{x - 1}, - \frac{1 - 5 x}{x - 1}

What is the inverse of (x^2+1)/(x^2+5) ?
The inverse of (x^2+1)/(x^2+5) is sqrt((1-5x)/(x-1)),-sqrt((1-5x)/(x-1))