What is the inverse of y= 1/40 ln(0.1x)+30 ?

The inverse of y= 1/40 ln(0.1x)+30 is e^{40x-1200}*10

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inverse of y= 1/40 ln(0.1x)+30

inverse

y = \frac{1}{40} ln (0.1 x) + 30

e^{40 x - 1200} \cdot 10

Solution steps

y = \frac{1}{40} ln (0.1 x) + 30

Replace

x

with

y

x = \frac{1}{40} ln (0.1 y) + 30

Solve for

y, x = \frac{1}{40} ln (0.1 y) + 30

e^{40 x - 1200} \cdot 10

What is the inverse of y= 1/40 ln(0.1x)+30 ?
The inverse of y= 1/40 ln(0.1x)+30 is e^{40x-1200}*10