What is the inverse of y= 1/(1-e^{\frac{-x){2}}} ?

The inverse of y= 1/(1-e^{\frac{-x){2}}} is ln((x^2)/(x^2-2x+1))

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inverse of y= 1/(1-e^{\frac{-x){2}}}

inverse

y = \frac{1}{1 - e ^{\frac{- x}{2}}}

ln (\frac{x ^{2}}{x ^{2} - 2 x + 1})

Solution steps

y = \frac{1}{1 - e ^{\frac{- x}{2}}}

Replace

x

with

y

x = \frac{1}{1 - e ^{\frac{- y}{2}}}

Solve for

y, x = \frac{1}{1 - e ^{\frac{- y}{2}}}

ln (\frac{x ^{2}}{x ^{2} - 2 x + 1})

What is the inverse of y= 1/(1-e^{\frac{-x){2}}} ?
The inverse of y= 1/(1-e^{\frac{-x){2}}} is ln((x^2)/(x^2-2x+1))