What is the inverse of y= 1/40 e^{0.1x}+30 ?

The inverse of y= 1/40 e^{0.1x}+30 is (ln(40x-1200))/(0.1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of y= 1/40 e^{0.1x}+30

inverse

y = \frac{1}{40} e^{0.1 x} + 30

\frac{ln ( 40 x - 1200 )}{0.1}

Solution steps

y = \frac{1}{40} e^{0.1 x} + 30

Replace

x

with

y

x = \frac{1}{40} e^{0.1 y} + 30

Solve for

y, x = \frac{1}{40} e^{0.1 y} + 30

\frac{ln ( 40 x - 1200 )}{0.1}

What is the inverse of y= 1/40 e^{0.1x}+30 ?
The inverse of y= 1/40 e^{0.1x}+30 is (ln(40x-1200))/(0.1)