What is the inverse of f(x)=((x^2+5x)1)/2 ?

The inverse of f(x)=((x^2+5x)1)/2 is (-5+sqrt(25+8x))/2 ,(-5-sqrt(25+8x))/2

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inverse of f(x)=((x^2+5x)1)/2

inverse

f (x) = \frac{( x ^{2} + 5 x ) 1}{2}

\frac{- 5 + 25 + 8 x}{2}, \frac{- 5 - 25 + 8 x}{2}

Solution steps

y = \frac{( x ^{2} + 5 x ) \cdot 1}{2}

Replace

x

with

y

x = \frac{( y ^{2} + 5 y ) \cdot 1}{2}

Solve for

y, x = \frac{( y ^{2} + 5 y ) 1}{2}

\frac{- 5 + 25 + 8 x}{2}, \frac{- 5 - 25 + 8 x}{2}

What is the inverse of f(x)=((x^2+5x)1)/2 ?
The inverse of f(x)=((x^2+5x)1)/2 is (-5+sqrt(25+8x))/2 ,(-5-sqrt(25+8x))/2