What is the inverse of f(x)=2-3x^2,x<= 0 ?

The inverse of f(x)=2-3x^2,x<= 0 is sqrt(-(x-2)/3),-sqrt(-(x-2)/3)

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inverse of f(x)=2-3x^2,x<= 0

inverse

f (x) = 2 - 3 x^{2}, x \leq 0

- \frac{x - 2}{3}, - - \frac{x - 2}{3}

Solution steps

y = 2 - 3 x^{2}

Replace

x

with

y

x = 2 - 3 y^{2}

Solve for

y, x = 2 - 3 y^{2}

- \frac{x - 2}{3}, - - \frac{x - 2}{3}

What is the inverse of f(x)=2-3x^2,x<= 0 ?
The inverse of f(x)=2-3x^2,x<= 0 is sqrt(-(x-2)/3),-sqrt(-(x-2)/3)