What is the inverse of-3(y+2)^2+1 ?

The inverse of-3(y+2)^2+1 is sqrt(-(y-1)/3)-2,-sqrt(-(y-1)/3)-2

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inverse of-3(y+2)^2+1

inverse

- 3 (y + 2)^{2} + 1

- \frac{y - 1}{3} - 2, - - \frac{y - 1}{3} - 2

Solution steps

y = - 3 (y + 2)^{2} + 1

Replace

y

with

y

y = - 3 (y + 2)^{2} + 1

Solve for

y, y = - 3 (y + 2)^{2} + 1

- \frac{y - 1}{3} - 2, - - \frac{y - 1}{3} - 2

What is the inverse of-3(y+2)^2+1 ?
The inverse of-3(y+2)^2+1 is sqrt(-(y-1)/3)-2,-sqrt(-(y-1)/3)-2