What is the inverse of f(x)= 1/(x^2)+2 ?

The inverse of f(x)= 1/(x^2)+2 is sqrt(1/(x-2)),-sqrt(1/(x-2))

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inverse of f(x)= 1/(x^2)+2

inverse

f (x) = \frac{1}{x ^{2}} + 2

\frac{1}{x - 2}, - \frac{1}{x - 2}

Solution steps

y = \frac{1}{x ^{2}} + 2

Replace

x

with

y

x = \frac{1}{y ^{2}} + 2

Solve for

y, x = \frac{1}{y ^{2}} + 2

\frac{1}{x - 2}, - \frac{1}{x - 2}

What is the inverse of f(x)= 1/(x^2)+2 ?
The inverse of f(x)= 1/(x^2)+2 is sqrt(1/(x-2)),-sqrt(1/(x-2))