What is the inverse of y= x/(x^2-6x+8),(-2<x<2) ?

The inverse of y= x/(x^2-6x+8),(-2<x<2) is (6x+1+sqrt(4x^2+12x+1))/(2x),(6x+1-sqrt(4x^2+12x+1))/(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of y= x/(x^2-6x+8),(-2<x<2)

inverse

y = \frac{x}{x ^{2} - 6 x + 8}, (- 2 < x < 2)

\frac{6 x + 1 + 4 x ^{2} + 12 x + 1}{2 x}, \frac{6 x + 1 - 4 x ^{2} + 12 x + 1}{2 x}

Solution steps

y = \frac{x}{x ^{2} - 6 x + 8}

Replace

x

with

y

x = \frac{y}{y ^{2} - 6 y + 8}

Solve for

y, x = \frac{y}{y ^{2} - 6 y + 8}

\frac{6 x + 1 + 4 x ^{2} + 12 x + 1}{2 x}, \frac{6 x + 1 - 4 x ^{2} + 12 x + 1}{2 x}

What is the inverse of y= x/(x^2-6x+8),(-2<x<2) ?
The inverse of y= x/(x^2-6x+8),(-2<x<2) is (6x+1+sqrt(4x^2+12x+1))/(2x),(6x+1-sqrt(4x^2+12x+1))/(2x)