What is the inverse of y=(-1)/4 (x+2)^2+1 ?

The inverse of y=(-1)/4 (x+2)^2+1 is 2sqrt(-x+1)-2,-2sqrt(-x+1)-2

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inverse of y=(-1)/4 (x+2)^2+1

inverse

y = \frac{- 1}{4} (x + 2)^{2} + 1

2 - x + 1 - 2, - 2 - x + 1 - 2

Solution steps

y = \frac{- 1}{4} (x + 2)^{2} + 1

Replace

x

with

y

x = \frac{- 1}{4} (y + 2)^{2} + 1

Solve for

y, x = \frac{- 1}{4} (y + 2)^{2} + 1

2 - x + 1 - 2, - 2 - x + 1 - 2

What is the inverse of y=(-1)/4 (x+2)^2+1 ?
The inverse of y=(-1)/4 (x+2)^2+1 is 2sqrt(-x+1)-2,-2sqrt(-x+1)-2