What is the inverse of f(x)= 1/4 x^2+x-1 ?

The inverse of f(x)= 1/4 x^2+x-1 is 2(sqrt(x+2)-1),-2(sqrt(x+2)+1)

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inverse of f(x)= 1/4 x^2+x-1

inverse

f (x) = \frac{1}{4} x^{2} + x - 1

2 (x + 2 - 1), - 2 (x + 2 + 1)

Solution steps

y = \frac{1}{4} x^{2} + x - 1

Replace

x

with

y

x = \frac{1}{4} y^{2} + y - 1

Solve for

y, x = \frac{1}{4} y^{2} + y - 1

2 (x + 2 - 1), - 2 (x + 2 + 1)

What is the inverse of f(x)= 1/4 x^2+x-1 ?
The inverse of f(x)= 1/4 x^2+x-1 is 2(sqrt(x+2)-1),-2(sqrt(x+2)+1)