What is the inverse of (3x)/(sqrt(8x^2-9)) ?

The inverse of (3x)/(sqrt(8x^2-9)) is (3xsqrt(8x^2-9))/(8x^2-9),-(3xsqrt(8x^2-9))/(8x^2-9)

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inverse of (3x)/(sqrt(8x^2-9))

inverse

\frac{3 x}{8 x ^{2} - 9}

\frac{3 x 8 x ^{2} - 9}{8 x ^{2} - 9}, - \frac{3 x 8 x ^{2} - 9}{8 x ^{2} - 9}

Solution steps

y = \frac{3 x}{8 x ^{2} - 9}

Replace

x

with

y

x = \frac{3 y}{8 y ^{2} - 9}

Solve for

y, x = \frac{3 y}{8 y ^{2} - 9}

\frac{3 x 8 x ^{2} - 9}{8 x ^{2} - 9}, - \frac{3 x 8 x ^{2} - 9}{8 x ^{2} - 9}

What is the inverse of (3x)/(sqrt(8x^2-9)) ?
The inverse of (3x)/(sqrt(8x^2-9)) is (3xsqrt(8x^2-9))/(8x^2-9),-(3xsqrt(8x^2-9))/(8x^2-9)