What is the inverse of f(x)=-16x^2+63x+5 ?

The inverse of f(x)=-16x^2+63x+5 is -(-63+sqrt(-64x+4289))/(32),-(-63-sqrt(-64x+4289))/(32)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=-16x^2+63x+5

inverse

f (x) = - 16 x^{2} + 63 x + 5

- \frac{- 63 + - 64 x + 4289}{32}, - \frac{- 63 - - 64 x + 4289}{32}

Solution steps

y = - 16 x^{2} + 63 x + 5

Replace

x

with

y

x = - 16 y^{2} + 63 y + 5

Solve for

y, x = - 16 y^{2} + 63 y + 5

- \frac{- 63 + - 64 x + 4289}{32}, - \frac{- 63 - - 64 x + 4289}{32}

What is the inverse of f(x)=-16x^2+63x+5 ?
The inverse of f(x)=-16x^2+63x+5 is -(-63+sqrt(-64x+4289))/(32),-(-63-sqrt(-64x+4289))/(32)