What is the inverse of 2x^2+8x-8 ?

The inverse of 2x^2+8x-8 is (-8+sqrt(8x+128))/4 ,(-8-sqrt(8x+128))/4

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inverse of 2x^2+8x-8

inverse

2 x^{2} + 8 x - 8

\frac{- 8 + 8 x + 128}{4}, \frac{- 8 - 8 x + 128}{4}

Solution steps

y = 2 x^{2} + 8 x - 8

Replace

x

with

y

x = 2 y^{2} + 8 y - 8

Solve for

y, x = 2 y^{2} + 8 y - 8

\frac{- 8 + 8 x + 128}{4}, \frac{- 8 - 8 x + 128}{4}

What is the inverse of 2x^2+8x-8 ?
The inverse of 2x^2+8x-8 is (-8+sqrt(8x+128))/4 ,(-8-sqrt(8x+128))/4