What is the inverse of f(x)=(x^3+4)^{1/5}-3 ?

The inverse of f(x)=(x^3+4)^{1/5}-3 is cube root of x^5+15x^4+90x^3+270x^2+405x+239

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inverse of f(x)=(x^3+4)^{1/5}-3

inverse

f (x) = (x^{3} + 4)^{\frac{1}{5}} - 3

Solution steps

y = (x^{3} + 4)^{\frac{1}{5}} - 3

Replace

x

with

y

x = (y^{3} + 4)^{\frac{1}{5}} - 3

Solve for

y, x = (y^{3} + 4)^{\frac{1}{5}} - 3

What is the inverse of f(x)=(x^3+4)^{1/5}-3 ?
The inverse of f(x)=(x^3+4)^{1/5}-3 is cube root of x^5+15x^4+90x^3+270x^2+405x+239