What is the inverse of f(x)= 1/((1-x)^2) ?

The inverse of f(x)= 1/((1-x)^2) is -sqrt(1/x)+1,sqrt(1/x)+1

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inverse of f(x)= 1/((1-x)^2)

inverse

f (x) = \frac{1}{( 1 - x ) ^{2}}

- \frac{1}{x} + 1, \frac{1}{x} + 1

Solution steps

y = \frac{1}{( 1 - x ) ^{2}}

Replace

x

with

y

x = \frac{1}{( 1 - y ) ^{2}}

Solve for

y, x = \frac{1}{( 1 - y ) ^{2}}

- \frac{1}{x} + 1, \frac{1}{x} + 1

What is the inverse of f(x)= 1/((1-x)^2) ?
The inverse of f(x)= 1/((1-x)^2) is -sqrt(1/x)+1,sqrt(1/x)+1