What is the critical f(x)=5x^2(3^x) ?

The critical f(x)=5x^2(3^x) is x=-2/(ln(3)),x=0

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critical f(x)=5x^2(3^x)

critical points

f (x) = 5 x^{2} (3^{x})

x = - \frac{2}{ln ( 3 )}, x = 0

Solution steps

5 x^{2} \cdot 3^{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2}{ln ( 3 )}, x = 0

Identify critical points not in

f (x)

domain

Domain of

5 x^{2} 3^{x} : - \infty < x < \infty

All critical points are in domain

x = - \frac{2}{ln ( 3 )}, x = 0

f (x) = 3 x - 2

y = - (x + 1)^{2}

(0, 7), (6, 9)

\frac{1}{x ^{3} - 2 x ^{2}}

f (x) = \frac{10}{x ^{2} - 4}

What is the critical f(x)=5x^2(3^x) ?
The critical f(x)=5x^2(3^x) is x=-2/(ln(3)),x=0