What is the inverse of 1/(sqrt(9-x^2)) ?

The inverse of 1/(sqrt(9-x^2)) is sqrt(-(1-9x^2)/(x^2)),-sqrt(-(1-9x^2)/(x^2))

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inverse of 1/(sqrt(9-x^2))

inverse

\frac{1}{9 - x ^{2}}

- \frac{1 - 9 x ^{2}}{x ^{2}}, - - \frac{1 - 9 x ^{2}}{x ^{2}}

Solution steps

y = \frac{1}{9 - x ^{2}}

Replace

x

with

y

x = \frac{1}{9 - y ^{2}}

Solve for

y, x = \frac{1}{9 - y ^{2}}

- \frac{1 - 9 x ^{2}}{x ^{2}}, - - \frac{1 - 9 x ^{2}}{x ^{2}}

What is the inverse of 1/(sqrt(9-x^2)) ?
The inverse of 1/(sqrt(9-x^2)) is sqrt(-(1-9x^2)/(x^2)),-sqrt(-(1-9x^2)/(x^2))