What is the inverse of f(x)=sqrt(x^2+2x-1) ?

The inverse of f(x)=sqrt(x^2+2x-1) is -1+sqrt(x^2+2),-sqrt(x^2+2)-1

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inverse of f(x)=sqrt(x^2+2x-1)

inverse

f (x) = x^{2} + 2 x - 1

- 1 + x^{2} + 2, - x^{2} + 2 - 1

Solution steps

y = x^{2} + 2 x - 1

Replace

x

with

y

x = y^{2} + 2 y - 1

Solve for

y, x = y^{2} + 2 y - 1

- 1 + x^{2} + 2, - x^{2} + 2 - 1

What is the inverse of f(x)=sqrt(x^2+2x-1) ?
The inverse of f(x)=sqrt(x^2+2x-1) is -1+sqrt(x^2+2),-sqrt(x^2+2)-1