What is the inverse of (2s-5)/(s^2+4) ?

The inverse of (2s-5)/(s^2+4) is (1+sqrt(-s(4s+5)+1))/s ,(1-sqrt(-s(4s+5)+1))/s

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inverse of (2s-5)/(s^2+4)

inverse

\frac{2 s - 5}{s ^{2} + 4}

\frac{1 + - s ( 4 s + 5 ) + 1}{s}, \frac{1 - - s ( 4 s + 5 ) + 1}{s}

Solution steps

y = \frac{2 s - 5}{s ^{2} + 4}

Replace

s

with

y

s = \frac{2 y - 5}{y ^{2} + 4}

Solve for

y, s = \frac{2 y - 5}{y ^{2} + 4}

\frac{1 + - s ( 4 s + 5 ) + 1}{s}, \frac{1 - - s ( 4 s + 5 ) + 1}{s}

What is the inverse of (2s-5)/(s^2+4) ?
The inverse of (2s-5)/(s^2+4) is (1+sqrt(-s(4s+5)+1))/s ,(1-sqrt(-s(4s+5)+1))/s