What is the critical f(x)=x^2ln(x/2) ?

The critical f(x)=x^2ln(x/2) is x= 2/(sqrt(e))

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critical f(x)=x^2ln(x/2)

critical points

f (x) = x^{2} ln (\frac{x}{2})

x = \frac{2}{e}

Solution steps

x^{2} ln (\frac{x}{2})

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{2}{e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} ln (\frac{x}{2}) : x > 0

x^{2} ln (\frac{x}{2})

is not defined at

x = 0

, therefore:

x = \frac{2}{e}

f (x) = - 16 x^{2} + 60 x + 2

m = \frac{1}{3}

x^{2} - 25

x 8 - x^{2}

f (x) = \frac{x + 4}{x - 5}

What is the critical f(x)=x^2ln(x/2) ?
The critical f(x)=x^2ln(x/2) is x= 2/(sqrt(e))