What is the inverse of log_{e}(x+2)+log_{e}(x-2)+pi ?

The inverse of log_{e}(x+2)+log_{e}(x-2)+pi is sqrt(e^{x-pi)+4},-sqrt(e^{x-pi)+4}

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inverse of log_{e}(x+2)+log_{e}(x-2)+pi

inverse

lo g_{e} (x + 2) + lo g_{e} (x - 2) + π

e^{x - π} + 4, - e^{x - π} + 4

Solution steps

y = lo g_{e} (x + 2) + lo g_{e} (x - 2) + π

Replace

x

with

y

x = lo g_{e} (y + 2) + lo g_{e} (y - 2) + π

Solve for

y, x = lo g_{e} (y + 2) + lo g_{e} (y - 2) + π

e^{x - π} + 4, - e^{x - π} + 4

What is the inverse of log_{e}(x+2)+log_{e}(x-2)+pi ?
The inverse of log_{e}(x+2)+log_{e}(x-2)+pi is sqrt(e^{x-pi)+4},-sqrt(e^{x-pi)+4}