What is the inverse of f(x)=log_{3}(1-2x+x^2) ?

The inverse of f(x)=log_{3}(1-2x+x^2) is 1+sqrt(3^x),1-sqrt(3^x)

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inverse of f(x)=log_{3}(1-2x+x^2)

inverse

f (x) = lo g_{3} (1 - 2 x + x^{2})

1 + 3^{x}, 1 - 3^{x}

Solution steps

y = lo g_{3} (1 - 2 x + x^{2})

Replace

x

with

y

x = lo g_{3} (1 - 2 y + y^{2})

Solve for

y, x = lo g_{3} (1 - 2 y + y^{2})

1 + 3^{x}, 1 - 3^{x}

What is the inverse of f(x)=log_{3}(1-2x+x^2) ?
The inverse of f(x)=log_{3}(1-2x+x^2) is 1+sqrt(3^x),1-sqrt(3^x)