What is the inverse of 1/3 (x-4)^2+2 ?

The inverse of 1/3 (x-4)^2+2 is sqrt(3x-6)+4,-sqrt(3x-6)+4

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inverse of 1/3 (x-4)^2+2

inverse

\frac{1}{3} (x - 4)^{2} + 2

3 x - 6 + 4, - 3 x - 6 + 4

Solution steps

y = \frac{1}{3} (x - 4)^{2} + 2

Replace

x

with

y

x = \frac{1}{3} (y - 4)^{2} + 2

Solve for

y, x = \frac{1}{3} (y - 4)^{2} + 2

3 x - 6 + 4, - 3 x - 6 + 4

What is the inverse of 1/3 (x-4)^2+2 ?
The inverse of 1/3 (x-4)^2+2 is sqrt(3x-6)+4,-sqrt(3x-6)+4