What is the domain of f(x)=sqrt(x^2+x+2) ?

The domain of f(x)=sqrt(x^2+x+2) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+x+2)

domain

f (x) = x^{2} + x + 2

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = x^{5} = 2 x^{3} = x - 1

\frac{x + 8}{x - 4}

f (x) = 2 \cdot 3^{x - 1} - 4

f (x) = \frac{5 x + 2}{2 x - 3}

What is the domain of f(x)=sqrt(x^2+x+2) ?
The domain of f(x)=sqrt(x^2+x+2) is -infinity <x<infinity