What is the inverse of f(x)=x^2+3x+4 ?

The inverse of f(x)=x^2+3x+4 is (-3+sqrt(4x-7))/2 ,(-3-sqrt(4x-7))/2

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inverse of f(x)=x^2+3x+4

inverse

f (x) = x^{2} + 3 x + 4

\frac{- 3 + 4 x - 7}{2}, \frac{- 3 - 4 x - 7}{2}

Solution steps

y = x^{2} + 3 x + 4

Replace

x

with

y

x = y^{2} + 3 y + 4

Solve for

y, x = y^{2} + 3 y + 4

\frac{- 3 + 4 x - 7}{2}, \frac{- 3 - 4 x - 7}{2}

What is the inverse of f(x)=x^2+3x+4 ?
The inverse of f(x)=x^2+3x+4 is (-3+sqrt(4x-7))/2 ,(-3-sqrt(4x-7))/2