What is the critical f(x)=x^3+3x^2-72x ?

The critical f(x)=x^3+3x^2-72x is x=-6,x=4

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critical f(x)=x^3+3x^2-72x

critical points

f (x) = x^{3} + 3 x^{2} - 72 x

x = - 6, x = 4

Solution steps

x^{3} + 3 x^{2} - 72 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 6, x = 4

Identify critical points not in

f (x)

domain

Domain of

x^{3} + 3 x^{2} - 72 x : - \infty < x < \infty

All critical points are in domain

x = - 6, x = 4

8 x^{4} - 8 x^{2} + 1

1

(- 4, - 5), (- 5, 5)

f (x) = \frac{( 5 x + 25 )}{x}

f (x) = - \frac{3}{2} (1.5)^{x}

What is the critical f(x)=x^3+3x^2-72x ?
The critical f(x)=x^3+3x^2-72x is x=-6,x=4