What is the critical f(x)= 1/2 x^2+3x+7 ?

The critical f(x)= 1/2 x^2+3x+7 is x=-3

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critical f(x)= 1/2 x^2+3x+7

critical points

f (x) = \frac{1}{2} x^{2} + 3 x + 7

x = - 3

Solution steps

\frac{1}{2} x^{2} + 3 x + 7

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{2} x^{2} + 3 x + 7 : - \infty < x < \infty

All critical points are in domain

x = - 3

f (x) = \frac{4 x}{6 x ^{2} + 13 x - 5}

x = y^{2} - 9

3 x^{4} - 16 x^{3} + 24 x^{2}

f (x) = \frac{x + 1}{x ^{2} + 1}

x + 3

What is the critical f(x)= 1/2 x^2+3x+7 ?
The critical f(x)= 1/2 x^2+3x+7 is x=-3