What is the inverse of x/(sqrt(x^2+1/20)) ?

The inverse of x/(sqrt(x^2+1/20)) is sqrt(-(x^2)/(20(x^2-1))),-sqrt(-(x^2)/(20(x^2-1)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of x/(sqrt(x^2+1/20))

inverse

\frac{x}{x ^{2} + \frac{1}{20}}

- \frac{x ^{2}}{20 ( x ^{2} - 1 )}, - - \frac{x ^{2}}{20 ( x ^{2} - 1 )}

Solution steps

y = \frac{x}{x ^{2} + \frac{1}{20}}

Replace

x

with

y

x = \frac{y}{y ^{2} + \frac{1}{20}}

Solve for

y, x = \frac{y}{y ^{2} + \frac{1}{20}}

- \frac{x ^{2}}{20 ( x ^{2} - 1 )}, - - \frac{x ^{2}}{20 ( x ^{2} - 1 )}

What is the inverse of x/(sqrt(x^2+1/20)) ?
The inverse of x/(sqrt(x^2+1/20)) is sqrt(-(x^2)/(20(x^2-1))),-sqrt(-(x^2)/(20(x^2-1)))