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Popular >

extreme y=e^{-x^2}

Solution

extreme points

y = e^{- x^{2}}

Solution

Maximum (0, 1)

Solution steps

f^{'} (x) = - 2 e^{- x^{2}} x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

e^{- x^{2}} : 1

Maximum (0, 1)

Popular Examples

inverse of f(x)=((5x-3))/((2x+5))inverse

f (x) = \frac{( 5 x - 3 )}{( 2 x + 5 )}

slope of y+4=10(x+1)slope

y + 4 = 10 (x + 1)

critical f(x)= x/(x+2)critical points

f (x) = \frac{x}{x + 2}

inverse of 5 inverse

5

inverse of f(x)=\sqrt[3]{5x-2}inverse

Frequently Asked Questions (FAQ)

What is the extreme y=e^{-x^2} ?
The extreme y=e^{-x^2} is Maximum(0,1)