What is the inverse of f(x)= 3/5 x^3-9 ?

The inverse of f(x)= 3/5 x^3-9 is cube root of (5x+45)/3

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inverse of f(x)= 3/5 x^3-9

inverse

f (x) = \frac{3}{5} x^{3} - 9

Solution steps

y = \frac{3}{5} x^{3} - 9

Replace

x

with

y

x = \frac{3}{5} y^{3} - 9

Solve for

y, x = \frac{3}{5} y^{3} - 9

y = - x^{2} + 12 x - 35

f (x) = - 3 sin (2 x - 10) - 3

f (x) = \frac{x - 3}{x + 7}

y = x + 1

f (x) = x^{3} - 4 x^{2} - x + 4

What is the inverse of f(x)= 3/5 x^3-9 ?
The inverse of f(x)= 3/5 x^3-9 is cube root of (5x+45)/3