What is the inverse of f(x)=-3(y-1)^2+2 ?

The inverse of f(x)=-3(y-1)^2+2 is sqrt(-(y-2)/3)+1,-sqrt(-(y-2)/3)+1

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inverse of f(x)=-3(y-1)^2+2

inverse

f (x) = - 3 (y - 1)^{2} + 2

- \frac{y - 2}{3} + 1, - - \frac{y - 2}{3} + 1

Solution steps

x = - 3 (y - 1)^{2} + 2

Replace

y

with

x

y = - 3 (x - 1)^{2} + 2

Solve for

x, y = - 3 (x - 1)^{2} + 2

- \frac{y - 2}{3} + 1, - - \frac{y - 2}{3} + 1

What is the inverse of f(x)=-3(y-1)^2+2 ?
The inverse of f(x)=-3(y-1)^2+2 is sqrt(-(y-2)/3)+1,-sqrt(-(y-2)/3)+1