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Popular >

range of x^2+4x-12

Solution

range

x^{2} + 4 x - 12

Solution

f (x) \geq - 16

+1

Interval Notation

[- 16, \infty)

Solution steps

Vertex of

x^{2} + 4 x - 12 :

Minimum

(- 2, - 16)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 2, - 16)

f (x) \geq - 16

Popular Examples

domain of f(x)= 1/(1-ln(x))domain

f (x) = \frac{1}{1 - ln ( x )}

asymptotes of f(x)=(e^{2x})/x asymptotes

f (x) = \frac{e ^{2 x}}{x}

inflection f(x)=4x^3-48x-6 inflection points

f (x) = 4 x^{3} - 48 x - 6

domain of f(x)=log_{2}(4x+4)domain

f (x) = lo g_{2} (4 x + 4)

domain of f(x)= 2/x+4/(x+4)domain

f (x) = \frac{2}{x} + \frac{4}{x + 4}

Frequently Asked Questions (FAQ)

What is the range of x^2+4x-12 ?
The range of x^2+4x-12 is f(x)>=-16