What is the inverse of 2pir^2+2pirh ?

The inverse of 2pir^2+2pirh is (-pih+sqrt(pi(2r+pih^2)))/(2pi),-(pih+sqrt(pi(2r+pih^2)))/(2pi)

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inverse of 2pir^2+2pirh

inverse

2 π r^{2} + 2 π r h

\frac{- πh + π ( 2 r + π h ^{2} )}{2 π}, - \frac{πh + π ( 2 r + π h ^{2} )}{2 π}

Solution steps

y = 2 π r^{2} + 2 π r h

Replace

r

with

y

r = 2 π y^{2} + 2 π y h

Solve for

y, r = 2 π y^{2} + 2 π y h

\frac{- πh + π ( 2 r + π h ^{2} )}{2 π}, - \frac{πh + π ( 2 r + π h ^{2} )}{2 π}

What is the inverse of 2pir^2+2pirh ?
The inverse of 2pir^2+2pirh is (-pih+sqrt(pi(2r+pih^2)))/(2pi),-(pih+sqrt(pi(2r+pih^2)))/(2pi)