What is the inverse of 1/12 (6.5-x^2) ?

The inverse of 1/12 (6.5-x^2) is sqrt(-12x+6.5),-sqrt(-12x+6.5)

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inverse of 1/12 (6.5-x^2)

inverse

\frac{1}{12} (6.5 - x^{2})

- 12 x + 6.5, - - 12 x + 6.5

Solution steps

y = \frac{1}{12} (6.5 - x^{2})

Replace

x

with

y

x = \frac{1}{12} (6.5 - y^{2})

Solve for

y, x = \frac{1}{12} (6.5 - y^{2})

- 12 x + 6.5, - - 12 x + 6.5

What is the inverse of 1/12 (6.5-x^2) ?
The inverse of 1/12 (6.5-x^2) is sqrt(-12x+6.5),-sqrt(-12x+6.5)