What is the extreme f(x)=2x+5x^{2/5} ?

The extreme f(x)=2x+5x^{2/5} is Minimum(-1,3),Maximum(0,0)

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extreme f(x)=2x+5x^{2/5}

extreme points

f (x) = 2 x + 5 x^{\frac{2}{5}}

Minimum (- 1, 3), Maximum (0, 0)

Solution steps

f^{'} (x) = 2 + \frac{2}{x ^{\frac{3}{5}}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

2 x + 5 x^{\frac{2}{5}} : 3

Minimum (- 1, 3)

Plug

x = 0

into

2 x + 5 x^{\frac{2}{5}} : 0

Maximum (0, 0)

Minimum (- 1, 3), Maximum (0, 0)

f (x) = 6 x - 2

f (x) = \frac{3}{x - 6}

cos (2 x)

f (x) = x^{(\frac{9}{2})} - 7 x^{2}

2 x + 4

What is the extreme f(x)=2x+5x^{2/5} ?
The extreme f(x)=2x+5x^{2/5} is Minimum(-1,3),Maximum(0,0)