What is the inverse of f(x)=8(2x+10)^2+3,x>=-5 ?

The inverse of f(x)=8(2x+10)^2+3,x>=-5 is (sqrt(2)sqrt(x-3)-40)/8 ,(-sqrt(2)sqrt(x-3)-40)/8

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inverse of f(x)=8(2x+10)^2+3,x>=-5

inverse

f (x) = 8 (2 x + 10)^{2} + 3, x \geq - 5

\frac{2 x - 3 - 40}{8}, \frac{- 2 x - 3 - 40}{8}

Solution steps

y = 8 (2 x + 10)^{2} + 3

Replace

x

with

y

x = 8 (2 y + 10)^{2} + 3

Solve for

y, x = 8 (2 y + 10)^{2} + 3

\frac{2 x - 3 - 40}{8}, \frac{- 2 x - 3 - 40}{8}

What is the inverse of f(x)=8(2x+10)^2+3,x>=-5 ?
The inverse of f(x)=8(2x+10)^2+3,x>=-5 is (sqrt(2)sqrt(x-3)-40)/8 ,(-sqrt(2)sqrt(x-3)-40)/8