What is the domain of f(x)=sqrt(1+3/x) ?

The domain of f(x)=sqrt(1+3/x) is x 0

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domain of f(x)=sqrt(1+3/x)

domain

f (x) = 1 + \frac{3}{x}

x \leq - 3 or x > 0

Interval Notation

(- \infty, - 3] \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x > 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - 3 or x > 0

f (x) = - \frac{24}{x ^{4}}

f (x) = 5 x + 10

y = x^{2} + 2 x

f (x) = \frac{20 - 9 x}{5}

\frac{x + 3}{x ^{2} - 1}

What is the domain of f(x)=sqrt(1+3/x) ?
The domain of f(x)=sqrt(1+3/x) is x<=-3\lor x>0