What is the inverse of f(x)=(3x^2+5)/2 ?

The inverse of f(x)=(3x^2+5)/2 is sqrt((2x-5)/3),-sqrt((2x-5)/3)

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inverse of f(x)=(3x^2+5)/2

inverse

f (x) = \frac{3 x ^{2} + 5}{2}

\frac{2 x - 5}{3}, - \frac{2 x - 5}{3}

Solution steps

y = \frac{3 x ^{2} + 5}{2}

Replace

x

with

y

x = \frac{3 y ^{2} + 5}{2}

Solve for

y, x = \frac{3 y ^{2} + 5}{2}

\frac{2 x - 5}{3}, - \frac{2 x - 5}{3}

What is the inverse of f(x)=(3x^2+5)/2 ?
The inverse of f(x)=(3x^2+5)/2 is sqrt((2x-5)/3),-sqrt((2x-5)/3)