What is the inverse of f(x)=10ln(40t-1200) ?

The inverse of f(x)=10ln(40t-1200) is (e^{t/(10)}+1200)/(40)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=10ln(40t-1200)

inverse

f (x) = 10 ln (40 t - 1200)

\frac{e ^{\frac{t}{10}} + 1200}{40}

Solution steps

x = 10 ln (40 t - 1200)

Replace

t

with

x

t = 10 ln (40 x - 1200)

Solve for

x, t = 10 ln (40 x - 1200)

\frac{e ^{\frac{t}{10}} + 1200}{40}

What is the inverse of f(x)=10ln(40t-1200) ?
The inverse of f(x)=10ln(40t-1200) is (e^{t/(10)}+1200)/(40)