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Popular Functions >

inverse of f(x)=(x+1)/(x^2-2-x)

Solution

inverse

f (x) = \frac{x + 1}{x ^{2} - 2 - x}

Solution

\frac{1}{x} + 2

Solution steps

y = \frac{x + 1}{x ^{2} - 2 - x}

Replace

x

with

y

x = \frac{y + 1}{y ^{2} - 2 - y}

Solve for

y, x = \frac{y + 1}{y ^{2} - 2 - y}

\frac{1}{x} + 2

Graph

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Frequently Asked Questions (FAQ)

What is the inverse of f(x)=(x+1)/(x^2-2-x) ?
The inverse of f(x)=(x+1)/(x^2-2-x) is 1/x+2