What is the inverse of f(x)=sqrt(x^2+5x) ?

The inverse of f(x)=sqrt(x^2+5x) is (-5+sqrt(25+4x^2))/2 ,(-5-sqrt(25+4x^2))/2

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inverse of f(x)=sqrt(x^2+5x)

inverse

f (x) = x^{2} + 5 x

\frac{- 5 + 25 + 4 x ^{2}}{2}, \frac{- 5 - 25 + 4 x ^{2}}{2}

Solution steps

y = x^{2} + 5 x

Replace

x

with

y

x = y^{2} + 5 y

Solve for

y, x = y^{2} + 5 y

\frac{- 5 + 25 + 4 x ^{2}}{2}, \frac{- 5 - 25 + 4 x ^{2}}{2}

f (x) = 2 x^{2} + 8 x + 11

\frac{x + 9}{5}

x^{3} cos (x)

f (x) = 3 x - 9

f (x) = \frac{3 x - 2}{x ^{2} - 3 x - 4}

What is the inverse of f(x)=sqrt(x^2+5x) ?
The inverse of f(x)=sqrt(x^2+5x) is (-5+sqrt(25+4x^2))/2 ,(-5-sqrt(25+4x^2))/2