What is the inverse of f(x)=(1-x^2)^{1/2} ?

The inverse of f(x)=(1-x^2)^{1/2} is sqrt(-x^2+1),-sqrt(-x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=(1-x^2)^{1/2}

inverse

f (x) = (1 - x^{2})^{\frac{1}{2}}

- x^{2} + 1, - - x^{2} + 1

Solution steps

y = (1 - x^{2})^{\frac{1}{2}}

Replace

x

with

y

x = (1 - y^{2})^{\frac{1}{2}}

Solve for

y, x = (1 - y^{2})^{\frac{1}{2}}

- x^{2} + 1, - - x^{2} + 1

What is the inverse of f(x)=(1-x^2)^{1/2} ?
The inverse of f(x)=(1-x^2)^{1/2} is sqrt(-x^2+1),-sqrt(-x^2+1)