What is the inverse of f(x)=3x^2+8 ?

The inverse of f(x)=3x^2+8 is sqrt((x-8)/3),-sqrt((x-8)/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=3x^2+8

inverse

f (x) = 3 x^{2} + 8

\frac{x - 8}{3}, - \frac{x - 8}{3}

Solution steps

y = 3 x^{2} + 8

Replace

x

with

y

x = 3 y^{2} + 8

Solve for

y, x = 3 y^{2} + 8

\frac{x - 8}{3}, - \frac{x - 8}{3}

f (x) = - 2 + 2 - x

f (x) = \frac{2 x}{x ^{2} + 1}

\frac{1}{8} x^{3} - x^{2}

- 2 sin (- 2 x)

What is the inverse of f(x)=3x^2+8 ?
The inverse of f(x)=3x^2+8 is sqrt((x-8)/3),-sqrt((x-8)/3)