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Popular Functions >

inverse of ln((x-1)/(x+1))

Solution

inverse

ln (\frac{x - 1}{x + 1})

Solution

\frac{- 1 - e ^{x}}{e ^{x} - 1}

Solution steps

y = ln (\frac{x - 1}{x + 1})

Replace

x

with

y

x = ln (\frac{y - 1}{y + 1})

Solve for

y, x = ln (\frac{y - 1}{y + 1})

\frac{- 1 - e ^{x}}{e ^{x} - 1}

Graph

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Frequently Asked Questions (FAQ)

What is the inverse of ln((x-1)/(x+1)) ?
The inverse of ln((x-1)/(x+1)) is (-1-e^x)/(e^x-1)