What is the inverse of y=2(x-4)^2-8 ?

The inverse of y=2(x-4)^2-8 is sqrt((x+8)/2)+4,-sqrt((x+8)/2)+4

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inverse of y=2(x-4)^2-8

inverse

y = 2 (x - 4)^{2} - 8

\frac{x + 8}{2} + 4, - \frac{x + 8}{2} + 4

Solution steps

y = 2 (x - 4)^{2} - 8

Replace

x

with

y

x = 2 (y - 4)^{2} - 8

Solve for

y, x = 2 (y - 4)^{2} - 8

\frac{x + 8}{2} + 4, - \frac{x + 8}{2} + 4

What is the inverse of y=2(x-4)^2-8 ?
The inverse of y=2(x-4)^2-8 is sqrt((x+8)/2)+4,-sqrt((x+8)/2)+4