What is the inverse of f(x)=f(x)=2(x-3)^2+5 ?

The inverse of f(x)=f(x)=2(x-3)^2+5 is sqrt((x-5)/2)+3,-sqrt((x-5)/2)+3

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inverse of f(x)=f(x)=2(x-3)^2+5

inverse

f (x) = f (x) = 2 (x - 3)^{2} + 5

\frac{x - 5}{2} + 3, - \frac{x - 5}{2} + 3

Solution steps

y = 2 (x - 3)^{2} + 5

Replace

x

with

y

x = 2 (y - 3)^{2} + 5

Solve for

y, x = 2 (y - 3)^{2} + 5

\frac{x - 5}{2} + 3, - \frac{x - 5}{2} + 3

What is the inverse of f(x)=f(x)=2(x-3)^2+5 ?
The inverse of f(x)=f(x)=2(x-3)^2+5 is sqrt((x-5)/2)+3,-sqrt((x-5)/2)+3