What is the inverse of (sqrt(x))/(x-7) ?

The inverse of (sqrt(x))/(x-7) is (14x^2+1+sqrt(28x^2+1))/(2x^2),(14x^2+1-sqrt(28x^2+1))/(2x^2)

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inverse of (sqrt(x))/(x-7)

inverse

\frac{x}{x - 7}

\frac{14 x ^{2} + 1 + 28 x ^{2} + 1}{2 x ^{2}}, \frac{14 x ^{2} + 1 - 28 x ^{2} + 1}{2 x ^{2}}

Solution steps

y = \frac{x}{x - 7}

Replace

x

with

y

x = \frac{y}{y - 7}

Solve for

y, x = \frac{y}{y - 7}

\frac{14 x ^{2} + 1 + 28 x ^{2} + 1}{2 x ^{2}}, \frac{14 x ^{2} + 1 - 28 x ^{2} + 1}{2 x ^{2}}

What is the inverse of (sqrt(x))/(x-7) ?
The inverse of (sqrt(x))/(x-7) is (14x^2+1+sqrt(28x^2+1))/(2x^2),(14x^2+1-sqrt(28x^2+1))/(2x^2)