What is the inverse of y= 1/3 log_{10}(x-1)+4 ?

The inverse of y= 1/3 log_{10}(x-1)+4 is 10^{3x-12}+1

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inverse of y= 1/3 log_{10}(x-1)+4

inverse

y = \frac{1}{3} lo g_{10} (x - 1) + 4

1 0^{3 x - 12} + 1

Solution steps

y = \frac{1}{3} lo g_{10} (x - 1) + 4

Replace

x

with

y

x = \frac{1}{3} lo g_{10} (y - 1) + 4

Solve for

y, x = \frac{1}{3} lo g_{10} (y - 1) + 4

1 0^{3 x - 12} + 1

What is the inverse of y= 1/3 log_{10}(x-1)+4 ?
The inverse of y= 1/3 log_{10}(x-1)+4 is 10^{3x-12}+1